Question

Find the area of the field ABCDEFG given alongside in which.
AB=30 m, AM = 70 m, AN= 90 m, AO = 110 m, AE= 135 m, AB = 36 m, LG = 40 m, NF = 42 m, MC= 54 m, and OD = 46 m,
please jaldi​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

AL=30 m

AM=70 m, AN=90 m,AO=110 m

AE=135 m,AB=36 m

LG=40, NF=42 m,MC=54 and OD=46 m

LM=AM-AL=70-30=40 m

MN=AN-AM=90-70=20 m

LN=LM+MN=40+20=60 m

NO=AO-AN=110-90=20 m

OE=AE-AO=135-110=25 m

NE=NO+OE=20+25=45 m

OM=MN+NO=20+20=40 m

Area of triangle=\frac{1}{2}\times base\times height

2

1

×base×height

Area of trapezium=\frac{1}{2}\times (sum\;of\;parallel\;sides)\times height

2

1

×(sumofparallelsides)×height

Area of ABCDEFG=Ar(ALG)+ar of trapezium(LNFG)+ar(FNE)+ar of trapezium(AMCB)+ar of trapezium(MCDO)+ar(OED)

Area of ABCDEFG=\frac{1}{2}(30)(40)+\frac{1}{2}(40+42)(60)+\frac{1}{2}(42)(45)+\frac{1}{2}(36+54)(70)+\frac{1}{2}(54+46)(40)+\frac{1}{2}(25)(46)

2

1

(30)(40)+

2

1

(40+42)(60)+

2

1

(42)(45)+

2

1

(36+54)(70)+

2

1

(54+46)(40)+

2

1

(25)(46)

Area of ABCDEFG=600+2460+945+3150+2000+575600+2460+945+3150+2000+575 square m