find the area of the field given below.
Answers
Answer:
the most biggest triangle at the bottom = having a point B and P and R along with two other points as the base . BQ = perpendicular.
area = 1/2×base×height
= 1/2 × ( 90+120+30+100) × 76 m²
= 1/2 × 340 × 76 m²
= 170 × 76 m²
= 12920 m² ( point i )
area of the left most triangle = 1/2 × base × height
1/2 × 90 × 95 m²
= 45 × 95 m²
= 4275 m² ( point 2 )
area of the right most triangle= 1/2 × base × height
= 1/2 × 100 × 125 m²
= 50 × 125 m²
= 6250 m² ( point 3 )
area of the middle quadrilateral =
first join the points ER and PD forming two triangles. ∆EPR and ∆DRE
hypotenuse of ∆EPR = √(height² + base²)
= √( 95² + 150²)
= √( 9025 + 22500)
= √( 31525)
= 177.56m
area of this triangle = 1/2 × base × height
= 1/2 × 150 × 95 m²
= 75 × 95 m²
= 7125 m² (point 4)
Now if we draw a parallel line from point E to the line DR , it will be equal to PR at point Z ( as there is a line and two perpendicular lines on it . and if those perpendicular lines r joined by a line parallel to the line on which those perpendicular lines r standing, we will get a rectangle , and opposite sides of a rectangle r equal , so EZ = PR = 150m
therefore, in ∆DRE , :-
height = EZ = 150m
base = DR = 120m
area = 1/2 × base × height
= 1/2 × 120 × 150m²
= 60 × 150m²
= 9000 m² ( point 5 )
by adding point 1,2,3,4 and 5 :-
= 12920+4275+6250+7125+9000 m²
= 39570 m²
ANSWER = 39570m²
Hope It Helped.
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Thanks!!
Answer:
Answer:
the most biggest triangle at the bottom = having a point B and P and R along with two other points as the base . BQ = perpendicular.
area = 1/2×base×height
= 1/2 × ( 90+120+30+100) × 76 m²
= 1/2 × 340 × 76 m²
= 170 × 76 m²
= 12920 m² ( point i )
area of the left most triangle = 1/2 × base × height
1/2 × 90 × 95 m²
= 45 × 95 m²
= 4275 m² ( point 2 )
area of the right most triangle= 1/2 × base × height
= 1/2 × 100 × 125 m²
= 50 × 125 m²
= 6250 m² ( point 3 )
area of the middle quadrilateral =
first join the points ER and PD forming two triangles. ∆EPR and ∆DRE
hypotenuse of ∆EPR = √(height² + base²)
= √( 95² + 150²)
= √( 9025 + 22500)
= √( 31525)
= 177.56m
area of this triangle = 1/2 × base × height
= 1/2 × 150 × 95 m²
= 75 × 95 m²
= 7125 m² (point 4)
Now if we draw a parallel line from point E to the line DR , it will be equal to PR at point Z ( as there is a line and two perpendicular lines on it . and if those perpendicular lines r joined by a line parallel to the line on which those perpendicular lines r standing, we will get a rectangle , and opposite sides of a rectangle r equal , so EZ = PR = 150m
therefore, in ∆DRE , :-
height = EZ = 150m
base = DR = 120m
area = 1/2 × base × height
= 1/2 × 120 × 150m²
= 60 × 150m²
= 9000 m² ( point 5 )
by adding point 1,2,3,4 and 5 :-
= 12920+4275+6250+7125+9000 m²
= 39570 m²
ANSWER = 39570m²
Hope It Helped.