Question

Find the area of the field given in the following figure:​

Answer 1

Step-by-step explanation:

For I,

• ½ ×25 ×20= 250 m²

For II,

• ½ (20+52)×40 = 1440m²

For III,

• ½ × 52× 56= 1456m²

For IV,

• ½ × 60× (25+40+56)= 3630m²

Total,

• 250+1440+1456+3630= 6776m²

I, III and IV are triangles so, the formula is ½×base×height.

II is a trapezium so, the formula is ½×(a+b)×height, where a and b are the parallel sides of the trapezium.

Answer 2

Answer:

area of the figure = area of region I + area of region II +  area of region III +  area of region IV

area of region I

1/2*bh

1/2*25*20

250 m^2

area of region II

1/2[a+b]h

1/2*72*40

1540m^2

area of region III

1/2*bh

1/2*56*52

1456 m^2

area of region IV

1/2*bh

base = 25m +40m + 56m = 121m

area = 1/2*121*60

       3630 m^2

area of the figure = [250 + 1540 + 1456 + 3630]m^2

                             =   6876 m^2