Question

find the area of the field shown in fig. ​

Answer 1

Answer:

1238 m^2

Step-by-step explanation:

First, we consider the right side

Area of the First triangle = bh/2

=> (4+12*24)/2

=> (16*24)/2

=>384/2

=> 192 unit^2

Area of second rectangle = lb

= (12+6)*24

= 18 * 24

= 432 unit^2

Area of the third triangle = bh/2

=> ((6+2)*24)/2

=> (8*24)/2

=> 192/2

=> 96 units^2

Next, we consider the left side of the figure

Ares of first triangle = bh/2

=> (16*12)/2

=> 192/2

=> 96 units ^2

Ares of the second rectangle = lb

=> 16*(4+12)

=> 16* 16

=> 256 m^2

Ares of the third trapezium = (a+b)h/2

=> (10+16)12/2

=> 26*12/2

=> 156m^2

Ares of forth triangle = bh/2

=> 10*2/2

=> 10 m^2

Therefore the area of the total figure = 192+432+96+92+256+156+10

                                                              = 1238 m^2

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