Question

find the area of the figure​

Answer 1

The Area of ABCD will be

= area of ∆ABC + Area of ∆ACD

$= \frac{1}{2} \times 75 \times 50 + \frac{1}{2} \times 75 \times 40$

simplify

$= 75 \times 25 + 75 \times 20$

$= 1875 + 1500$

$= 3375$

Answer 2

Step-by-step explanation:

$Area \: of \: ABCD -$

$ar(∆ABC) + ar(∆ACD)$

$\frac{1}{2}×AC×BE+\frac{1}{2}×AC×DF$

$\frac{1}{2} × AC × (BE + DF)$

$\frac{1}{2} × 75 × (50 + 40)$

$\frac{1}{2} × 75 × 90$

$75 × 45$

$75 × 9 × 5$

$675 × 5$

$3375 \: m²$