Question

Find the area of the figure ABCDEFG
where ABEG is a trapezium, BCDE is a rectangle,
and distance between AG and BE is 2 cm
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solve the question step by step..​

Answer 1

1st. Area of trapezium ABEG = 1/2 × sum of // side × height

AG = BE - GF = 8 - 3 = 5 cm

Now, Area = 1/2 × ( 8 + 5 ) × 2

= 1/2 × 13 × 2

= 13 cm sq. ..

2nd. Area of rectangle BCDE = length × breadth

= 2 × 8 = 16 cm sq.

3rd. Area of triangle = 1/2 × b × h

1/2 × 3 × 2 = 3 cm sq.

Hence , add eq. 1,2 and 3 , we get

= 13 + 16 +3 = 32 cm sq.