Question

Find the area of the figure formed by joining the points (5, 0), (0, 0), (0, 6).

Answer 1

AnsWer :

Area of shaded position be 15 Units.

Given :

• P1 = ( 5 , 0 )
• P2 = ( 0 , 0 )
• P3 = ( 0 , 6 )

Solution :

Let point be,

• A = ( 5 , 0 )
• B = ( 0 , 0 )
• C = ( 0 , 6 )

When we join Point A,B and C then triangle form.

So,

Area of triangle =

$\tt \dagger \: \: \: \frac{1}{2}[x_ 1(y_2 - y_1 ) + x_2(y_3-y_1)+x_3(y_1-y_2)]$

Where as,

• x1 = 5.
• x2 = 0.
• x3 = 6.
• y1 = 0.
• y2 = 0.
• y3 = 6.

$\tt\longmapsto \frac{1}{2} 5(0 - 6) + 0(6 - 0) + 0(0 - 0)$

$\tt\longmapsto \frac{1}{2} 5( - 6)$

$\tt\longmapsto \frac{1}{2} | - 30|$

$\tt\longmapsto \frac{1}{2} \times 30$

$\tt\longmapsto 15 \: units.$

Therefore, area of triangle be 15 Units.

$\rule{200}1$

Note : Graph provide above.

Some information :

• Area of triangle with Vertices, ABC.
• It always take positive with module sign. because area never be negative.