Question

Find the area of the figure formed by joining the points-
A(-4-2), B(3.-5), C(3,-2) and D(2,4)

Answer 1

Hey Mate find the answer in Image below

A(-4,-2) (x1,y1)

B(-3,-5) (x2,y2)

C(3,-2) (x3,y3)..

D(2,4) (x4,y4)

area(ABCD) = ar(ABC) + ar(ADC)

ar(∆) = ½ [x1(y2-y3) + x2(y3-y1) + x3(y1-y2)

ar(ABC) = ½ [-4(-5+2) - 3(-2+2) + 3(-2+5)]

= ½ [12+0+9]

= ½ [21]

10.5 unit²

similarly ar(ADC) = 21 unit²

therefore area of ABCD = 31.5 unit²

Or in image