Math, asked by pratyushssb, 1 year ago

Find the area of the figure formed by joining the points-
A(-4-2), B(3.-5), C(3,-2) and D(2,4)

Answers

Answered by Anonymous
9

Hey Mate find the answer in Image below

A(-4,-2) (x1,y1)

B(-3,-5) (x2,y2)

C(3,-2) (x3,y3)..

D(2,4) (x4,y4)


area(ABCD) = ar(ABC) + ar(ADC)

ar(∆) = ½ [x1(y2-y3) + x2(y3-y1) + x3(y1-y2)

ar(ABC) = ½ [-4(-5+2) - 3(-2+2) + 3(-2+5)]

= ½ [12+0+9]

= ½ [21]

10.5 unit²


similarly ar(ADC) = 21 unit²


therefore area of ABCD = 31.5 unit²


Or in image






pratyushssb: 31.5
Anonymous: see i have changed answer above
pratyushssb: Dude D is (2.4)
Anonymous: Ya i got that !! pls find the above ans without image
pratyushssb: okay thanks!
pratyushssb: hey area of other triangle is -21?
Anonymous: its 21 !
pratyushssb: why?
pratyushssb: is it absolute value ? ( the lines like this | .... | )
Anonymous: i think it approximate
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