Question

find the area of the figure given below​

Answer 1

Answer:

$114 {cm}^{2}$

Step-by-step explanation:

$db = \sqrt{( {17}^{2} - {8}^{2} )}$

$db = \sqrt{289 - 64} = \sqrt{225} = 15$

Similarly

AB=

$\sqrt{225 - 81} = \sqrt{144} = 12$

hence total area is

$\frac{1}{2} (12 \times 9) + \frac{1}{2} (8 \times 15)$

$\frac{1}{2} (228) = 114$

Answer 2

Step-by-step explanation:

in DBC

by Pythagoras theorem we can find DB

DB²= DC²-BC²

= (17)² - (8)²

= 289 - 64

= 225

DB = 15 CM

NOW

in DBC

area = 1/2 × base × height

= 1/2 × 8 × 15

= 60cm²

In DAB

by Pythagoras theorem we can find AB

AB² = DB² - DA²

= (15)² - (9)²

= 225 - 81

= 144

AB = 12cm

NOW in DAB

area = 1/2 × base × height

= 1/2 ×12 × 9

= 54 cm²

SO, THE AREA OF THE FIGURE IS

= area of DAB + area of DBC

= 54 cm² + 60 cm²

= 114 cm²