Find the area of the figure obtained by joining the midpoints of the adjacent sides of a rectangle of sides 8 cm and 6 cm
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If we will join the mid points
Then,
The formed figure will be rhombus
By Pythagoras theorem,
4²+3²=side of rhombus ²
5= side of rhombus
Diagonals of rhombus are 8 and 6
Area =8*6/2
Area =4*6
Area=24m²
I hope this is right and will help you
Then,
The formed figure will be rhombus
By Pythagoras theorem,
4²+3²=side of rhombus ²
5= side of rhombus
Diagonals of rhombus are 8 and 6
Area =8*6/2
Area =4*6
Area=24m²
I hope this is right and will help you
Shashank2810:
No
Since after joining the mid-points of the adjacent sides of a rectangle , we get a rhombus . Let ABCD is a rectangle and PQRS are midpoints of sides,so P
You are right bro
QRS is a rhombus , it’s diagonals PR=BC=y cm and SQ =AB=8cm
DE=1/2*/2*BC
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