Question

Find the area of the figure obtained by plotting the points (6, 5), (6,-3) and (-2,-3).​

Answer 1

area of triangle ABC

$\frac{1}{2} \: \: (x1(y2 - y3) + x2(y3 - y1) + x3(y1- y2))$

$\frac{1}{2} \: \: (6(( - 3 ) - ( - 3) + 6(( - 3) - 5 + - 2(5 - ( - 3)))$

$\frac{1}{2} \: \: \: 0 + 48 - 16$

$\frac{1}{2} \: \: \: \: 32$

$16$

$6 \times 0 + 6 \times 8 + - 2 \times 8$