Question

find the area of the figures given below ​

Answer 1

Answer:

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Answer 2

Answer:

Fig.1 2572cm²

Fig.2 1120cm²

Step-by-step explanation:

For fig. 1

The name of fig.1 be abcdef

Ar( abcdef) = ar(abcd) + ar(adef)

In abcd,

Area of triangle aop + area of rectangle opqr + area of triangle dqr = area if abcd

Area of abcd = ½(18*28) + (35*28) + ½(20*28) = 252cm² +980cm² +280cm² = 1512cm²

In adef

Area of triangle amo + area of rectangle mnro + area of triangle dnr = area of adef

Area of adef = ½(10*20) + (33*20) + ½(30*20) = 100cm² + 660cm² + 300cm² = 1060cm²

Hence area of fig. 1 abcdef

Area (abcdef) = 1060cm² + 1512 cm² = 2572cm²

In fig. 2

Let the name of fig. 2 be pqrst

Area of pqrst = area(pqrs) + area of triangle (pst)

In pqrs,

Area of pqrs = area of triangle poq + area of rectangle qrmo + area of triangle rsm = ½(14*16) + (14*24) + ½(14*16)=112cm² + 224cm² + 112 = 448cm²

In pst

Area of triangle rsm = ½(24*56) = 672cm²

Hence the area of fig. 2 pqrst

Area of pqrst = 448cm² + 672cm² = 1120cm²