find the area of the following figure
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in trapezium ABFC,
height of trapezium =43-18=25cm
AB=a=28cm FC=b=16cm
area of trapezium =1/2 ×h(a+b)=1/2×25(28+16)=1/2×25×44
=25×22=550cm²
area of rectangle FCED=l ×b=18×16=288cm²
area of given figure =550+288=838cm²
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