Question

find the area of the following figure​

Answer 1

$\sf \binom{area \: \: of \: \: }{quadrant} \sf = \frac{ \theta}{360 \degree} \times 2\pi r = \frac{ \cancel{90}}{ \cancel{360} }\times 2 \times 9 \times \pi$

$\sf = \frac{1}{ \cancel{4}} \times \cancel{ 18 }\times \pi = \frac{9}{2} \pi \: {mm}^{2}$

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Answer 2

Area = 63.585 mm²

Step by step explanation :-

Area of quadrant = 1/4(πr²)

= 1/4 × 314 ÷ 100 × 9 × 9

= 1/4 × 314 ÷ 100 × 81

= 1/4 × 81 × 314 ÷ 100

= 1/4 × 25,434 ÷ 100

= 6358.5 ÷ 100

= 63.585 mm²