Find the area of the following figure:-
Please give me solution.
Answer of this Question is 216 cm²
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Answer:
in the given quadrilateral PQRS,
construct a line QX perpendicular to SR
in triangle QRX,
RX=30-18=12m
side 1²+side2²=hypotenuse ²
RX²+QX²=QR²
12²+QX²=15²
144+QX²=225
QX²=225-144=81
QX=√81=9 m
area of triangle QRX=1/2 ×h×b=1/2 ×9×12=54m²
area of rectangle PQXS=l× b=18×9=162m²
area of quadrilateral PQRS=162+54=216m²
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