Question

find the area of the following figure whose dimension are shown​

Answer 1

Answer:

Step-by-step explanation:

Hint: Area of the portion ABPEF will remain same in case of point P lies anywhere on the line BE.

Area of the region ABPEF=ar(ΔABP)+ar(ΔEFP)

=  1/2  BP×20cm+  1/2 PE×20cm=  2 /1  ×20cm[BP+PE]=  2 /1 × 20cm×50cm=500 sq. cm].

Answer 2

Answer:

4400 cm²

Step-by-step explanation:

50 * 80 = 4000 cm ² = area of rect

20 *20 * ½ = 200 cm² = area of one triangle

area of two triangle = 400 cm²

so 4000 + 400 = 4400 cm²