Question

Find the area of the following picture

Answer 1

Answer:

The figure is divided into two quadrilateral: trapezium and rectangle

Area of trapezium=1/2×sum of parallels sides×height

1/2×( 5+8 ) × 4

1/2×13×4

26 cm²

Area of rectangle=length×breadth

5×8=40 cm²

Area of figure=area of trapezium+area of rectangle

26 + 40

66cm²

Answer 2

Step-by-step explanation:

first - area of trapezium =

$\frac{1}{2} (a + b)h$

so, = 1/2(5+8)*4

= 1/2 * 13*4

= 13*2

= 26cm

area of rectangle = L*B

= 8 * 5

= 40cm

so, 26 + 40

= 66 cm