find the area of the following polygon if a b c d and e f g h are isosceles and congruent trapezium
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4
Step-by-step explanation:
Area of CDEF "Rectangle" :- L x B
where L :- 5cm and B :- 28cm
so
Area :- ( 5 x 28 ) = 140cm²
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now area of two equal Trapezium:-
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Area of Trapezium :- (1/2)•(a+b)h
where:- a = 5cm ; b = 10cm ; h = (40-28) = 12cm
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Area of Two equal Trapezium is:- 2x(1/2)•(a+b)•h
2x(1/2)•(a+b)•h
2x(1/2)•(5+10)•(12)
(15x12)
180 cm²
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.
Totall Area of given figure:-
140 + 90 + 90
320cm²
Answered by
9
Step-by-step explanation:
this question's answer is 230 cm^2
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