Question

find the area of the following polygons​

Answer 1

$57{cm}^{2}$

is right answer this question...

sorry b/c pic is not clear

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Answer 2

The area of the polygon is $57\ cm^2$

Explanation:

The given figure consists of a trapezium and a triangle.

Area of trapezium =$\dfrac{1}{2}(\text{Sum of parallel sides) (height})$

Area of triangle =$\dfrac{1}{2}(\text{Base) (height})$

In trapezium,

Parallel sides of trapezium = 6 cm and 10 cm

height of trapezium = 4 cm

Area of trapezium = $\dfrac{1}{2}(6+10)(4)$

$=\dfrac{1}{2}(16)(4)$

$=(8)(4)=32\ cm^2$

In triangle,

Base = 10 cm

height = 5 cm

Area of triangle =  $\dfrac{1}{2}(10)(5)=25\ cm^2$

Now , Area of polygon = Area of trapezium+Area of triangle

$32\ cm^2+25\ cm^2=57\ cm^2$

Hence, the area of the polygon = $57\ cm^2$

#Learn more :

Find the area Of the polygon.​

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