find the area of the following quadrilateral with diagonal 8 cm and height 2 cm
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Answer:
BC=10cm
h1=5cm,h2=7cm
Area of Quadrilateral=area $$(\triangle ABC)+area (△BCD)
=21×BC×h1+21×BC×h2=(21×10×5+21×10×7)cm2=(25+35)cm2=60cm2
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Answer:
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60 cm²
Step-by-step explanation:
BC=10cm
h1=5cm,h2=7cm
Area of Quadrilateral=area $$(\triangle ABC)+area (△BCD)
=21×BC×h1+21×BC×h2=(21×10×5+21×10×7)cm2=(25+35)cm2=60cm2
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