find the area of the following quadrilaterals
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Answered by
5
hey mate
here is your answer
i)
area of ∆ABC
=18/2=9cm2
inADC
area of ∆ADC=15 cm2
area of aBCD =9+15=24cm2
ii) 14*6=84 cm2
iii)16 cm2
hope it helps
here is your answer
i)
area of ∆ABC
=18/2=9cm2
inADC
area of ∆ADC=15 cm2
area of aBCD =9+15=24cm2
ii) 14*6=84 cm2
iii)16 cm2
hope it helps
khalidrja78:
hiiii
Answered by
0
Answer:
Step-by-step explanation:
3rd one ans is 8 sqcm using formula 1/2×bh
1st ans is 24 sqcm using formula 1/2×d (h1+h2)
2nd ans is 21 sq cm using formula 1/2d1d2
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