Math, asked by ABCBEFGHIJKL, 1 year ago

find the area of the following quadrilaterals

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Answered by harindersaini2pcf8vf

Area of triangle = 1/2 × base × height

Step-by-step explanation:

(i) First we will divide this quadrilateral into two triangles that is triangle ABC and triangle ADC

Area of triangle ABC + Area of triangle ADC = Area of quadrilateral ABCD

=> ( 1/2 × 6 × 3 ) + ( 1/2 × 6 × 5 ) = 9 + 15 = 24 cm²

(ii) This shape is a rhombus because all sides are equal here and intersection angles of diagonals are 90°.

We have been given half the length of one diagonal and half the length of the other diagonal so,

Area of the rhombus = 1/2 × product of diagonals

= 1/2 × (7+7) × (6+6) = 1/2 × 14 × 12 = 84 cm²

(iii) The third shape is a parallelogram. We can see it has two equal opposite and parallel sides. A diagonal is dividing it into two congruent triangles of equal area.

So,

Area of the parallelogram = 2 × (1/2 × 8 × 2) = 2 × 8 = 16 cm²

ABCBEFGHIJKL: 7*6/2

ABCBEFGHIJKL: =21

ABCBEFGHIJKL: is it right

ABCBEFGHIJKL: hello

harindersaini2pcf8vf: Yes that is the formula of rhombus. But if we consider one diagonal then it gets divided into two different triangles.

harindersaini2pcf8vf: If you are not able to understand in this way then I'll do with the other methid

harindersaini2pcf8vf: *method

harindersaini2pcf8vf: Please tell the lengths of the diagonals...Are they 7 cm and 6 cm or are their halves 7 cm and 6 cm ??

ABCBEFGHIJKL: see the diagram

harindersaini2pcf8vf: Actually it's not so clear in the diagram. Once you can confirm from your teacher or any classmate about this.

Answered by anishkakontham

Answer:

Hope this is Helpful

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