Find the area of the following regular hexagon.
N
M
23 cm
13 cm
R
Р
Q
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Q. 8
4.2
( 32 Votes )
Find the area of
Class 8th
RS Aggarwal - Mathematics
18. Area of a Trapezium and a Polygon
Answer
Given: a regular hexagon ABCDEF
AB = BC = CD = DE = EF = FA = 13 cm
AD = 23 cm
Here AL = MD
Therefore Let AL = MD = x
Here AD = AL + LM + MD
23 = 13 + 2x
2x = 23 – 13 = 10
x = 5
Now,
In
ABL using Pythagoras theorem
AB2 = AL2 + LB2
132 = x2 + LB2
132 = 52 + LB2
169 = 25 + LB2
LB2 = 169 – 25 = 144
LB = 12
Here area (Trap. ABCD) = area (Trap. AFED)
Therefore,
Area (Hex. ABCDEF) = 2 × area (Trap. ABCD)
Area of trapezium =
× (sum of parallel sides) × height
Area (Trap. ABCD) =
× (BC + AD) × LB =
× (13 + 23) × 12 = 216 cm2.
Area(ABCDEFGH) = 2 × area (Trap. ABCD) = 2 × 216 = 432 cm2
Area(ABCDEFGH) = 432 cm2.
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