Question

find the area of the following trapezium if the perimeter of the trapezium is 80 DM

Answer 1

Step-by-step explanation:

Given that: if the perimeter of the trapezium is 80 dm.

To find: Area of Trapezium

Solution:

$\boxed{\bold{Area\:of\:Trapezium=\frac{1}{2} \times (sum \: of \: parallel \: sides) \times perpendicular \: distance}}$

As it is given that Perimeter of Trapezium is 80 dm

Sum of all sides= perimeter

$DC+BC+AD+AB=Perimeter\\\\28 + 14 + 22 + AB = 80 \\ \\ AB = 80 - 64 \\ \\ AB = 16 \: dm$

Since AB is perpendicular

Area of Trapezium

$=\frac{1}{2} \times ( AD+BC ) \times AB\\\\=\frac{1}{2} \times (22 + 14) \times 16 \\ \\ = \frac{1}{2} \times 36 \times 16 \\ \\ = 18 \times 16 \\ \\ = 288 \: {dm}^{2}$

Thus, area of given Trapezium is 288 sq-dm.

Hope it helps you.

Answer 2

Answer:

area is equals to 288 dm sq.

Step-by-step explanation:

hope it helps you dear