Find the area of the following trapeziums 7 cm 3 cm 9 cm
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Given parallel sides of trapezium are 7 cm,9 cm
Height of trapezium = 3 cm
Area of trapezium with parallel sides a,b and height h = 2(a+b)×h
Area of trapezium =2(7+9)×3=8×3=24sq.cm.
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Answer:
24 sq.cm
:
Find the area of the following Trapezium
Area of Trapezium = 1/2(a+b)×h sq. units
= 1/2×( 7+9 )×3
= 1×8×3 ( cut off 2 and 16 it gives 8 )
= 24 sq. CM
therefore, Area= 24 sq. cm
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