Question

Find the area of the following trapeziums .. height 2 cm Parallel sides 2.2 cm and 3.5 cm.
the answer is 5.7 cm ^2

plzzz explain it.

Answer 1

$\sf \large\: Question:$

$\sf \green{ \: The \: \: parallel \: \: sides \: of \: \: a \: trapezium \: are \: 2.2cm} \: \\ \sf \red{and \: 3.5cm. \: \: and distance \: \: between \: them is 2 cm.\: find \: \: the} \: \: \\ \sf \blue{Area \: of \: \: the \: \: Trapezium \: ?}$

$\sf \large\:Method \: of \: Solution:$

$\sf {\green {Trapezium: Trapezium \: is \: a \: quadrilateral \: \: means \: \: four \: \: sided}} \\ \: \sf{\red {closed\: \: figure \: \: in \: \: \: which \: a \: pair \: of \: \: opposite \: \: sides \: \: are \: \: parallel.}}$

$\sf{\small{ \green{Area \: of \: Trapezium}}} = \sf{ \red{(Sum \: of \: Parallel \: Side) \times \: }} \sf{ \blue{ (Distance \: between \: Them)}} \\ \\ \sf{ \green{ Area \: of \: Trapezium = (3.5+2.2)×2 \div 2}} \\ \\ \sf{ \red{Area \: of \: Trapezium = 11.4 \div 2}} \\ \\ \sf{\implies{ \sf{ \blue{(Area of \: Trapezium \:)}}}} = 5.7 {cm}^{2}$

Answer 2

Area of trapezium ABCD = Area of ∆ ABD + Area of ∆ CBD = 1/2 × a × h + 1/2 × b × h = 1/2 × h × (a + b) ... Find the area of a trapezium whose parallel sides are AB = 12 cm, CD = 36 cm and the ... The area of a trapezium is 165 cm² and its height is 10 

Worked-out examples on how do you find the area of a circle and the circumference ... Circumference of circle = 2πr. = 2 × 22/7 × 7. = 44 cm. Area of circle = πr².