Math, asked by kaurnavneet37746, 3 months ago

Find the area of the four walls of a room 8 m long,
6 m wide and 3 m high. If the room has one door
of dimensions 2 m x 1.5 m and two windows of
dimensions 1 m x 2.5 m, find the cost of painting
the walls of the room at the rate of 10.50/m2.

please solve step by step

answer will be 76m², rupees 798.... please tell me how to solve...step by step

Answers

Answered by Anonymous

Answer:

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Step-by-step explanation:

Answered by Anonymous

↪️ CSA of room = 2h (l+b)

↪️ CSA of room = 2×3 (8 + 6) m²

↪️ CSA of room = 6 × 14 m²

↪️ CSA of room = 84 mm²

↪️ Area of door = l×b

↪️ Area of door = 2 × 1.5 m²

↪️ Area of door = 3 m²

↪️ Area of window = 1 × 2.5 m²

↪️ Area of window = 2.5 m²

↪️ Area of two windows = 5 m²

↪️ Area to be painted = CSA of room - (Sum of areas of doors and windows)

↪️ Area to be painted = 84 - (5 + 3)

↪️ Area to be painted = 84 - 8

↪️ Area to be painted = 76 m²

↪️ Cost of painting = 10.50 × 76

↪️ Cost of painting = ₹ 798

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