Find the area of the four walls of a room whose length is 6m, breadth 5m and height 4m.Also find the cost of white washing if the rate of white washing is rupees 5 per square. meter
Answers
Answer:
Area=88m^2
cost = ₹440
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Given,
Dimensions of a room;
Length = L = 6 meters
Breadth = B = 5 meters
Height = H = 4 meters
Cost of whitewashing the walls per square meter area = Rs. 5
To find,
a) Total area of the four walls of the room
b) Total cost of whitewashing the four walls.
Solution,
We can simply solve this mathematical problem using the following process:
As per mensuration;
For a cuboid with length L, breadth B, and height H, the lateral surface of a cuboid
= 2H(L+B)
Now,
The total area of the four walls of the room
= the lateral surface of the room
= 2H(L+B)
= 2 x 4 m x (6m + 5m)
= 2 x 4 m x 11 m
= 88 square meters
Now,
The total cost of whitewashing the four walls
= (total area of the four walls of the room) x (cost of whitewashing the walls per square meter area)
= 88 square meters x Rs 5
= Rs. 440
Hence, the total area of the four walls of the room is equal to 88 square meters and the total cost of whitewashing the four walls is Rs. 440.