Question

find the area of the given figure
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Answer 1

Answer:

The Area of shaded region in

• first figure is 304 m²
• second figure is 4.7124 cm²

Step-by-step explanation:

• Let us take the first figure.

As we can see it is an Rectangle, so the opposite sides will be equal.

∴AD=BC=16m and AB=CD=24m

The inside figure is a Triangle whose base is nothing but the breadth of the Rectangle i.e., AD

Thus the dimensions of Triangle are

Base=AD=16m, Height=EF=10m.

Now, to find the area of shaded region, we need to remove the area of Triangle from the area of Rectangle.

∴Area of shaded portion=Area of Rectangle-Area of Triangle

WKT, Area of Rectangle=length×breadth and Area of Triangle=$\frac{1}{2}$×base×height

Area of shaded portion=(16×24)-($\frac{1}{2}$×16×10)

Area of shaded portion=384-80

∴Area of shaded portion=304 m²

• Now as for second figure it is a Semi-circle with another Semi-Circle inside it.

From figure we can say that,

the radius of outer Semi-Circle=2cm and,

the radius of inner Semi-Circle=1cm(the diameter is 2cm and as we know that radius=$\frac{diameter}{2}$)

Same as per the above problem

Area of shaded portion=(Area of outer Semi-Circle)-(Area of inner Semi-Circle)

Area of Semi-Circle=$\frac{1}{2}$πr²

∴Area of shaded portion=($\frac{1}{2}$×3.142×2²)-($\frac{1}{2}$×3.142×1²)

Area of shaded portion=6.283-1.571

∴Area of shaded portion=4.712 cm²