Find the area of the given figure
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sachi4268:
area of first trapezium =1\2×20×(10+30)=400cm. area of rectangle=b×h=10×50=500cm. are of second trapezium=400cm. area of figure =1+2+3(400+500+400)=1300cm this is the correct amd accurate answer hope it helps u and pls marj my ans as brainliest
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Answer:
its 1300*ithink you think
Step-by-step explanation:
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Given,
A figure with all dimensions mentioned.
To Find,
The area of the given figure.
Solution,
The given figure can be divided into 3 shapes that is one rectangle and two trapeziums.
Area of the rectangle = l*b = 50*10 = 500 cm².
Area of trapezium = (sum of parallel sides)*h/2
Area of trapezuim = (10+30)*10/2 = 200 cm².
Now,
Area of the figure = area of rectangle+2*area of the trapezium.
Area of the figure = 500+2*200 = 500+400 = 900 cm².
Hence, the area of the trapezium is 900 cm².
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