Question

Find the area of the given figure ABCDEFG as per
dimensions given in it (Fig. 3).​

Answer 1

Step-by-step explanation:

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +(

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 2

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 +

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 2

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21 ×40×150

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21 ×40×150=18,000+5400+3,000

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21 ×40×150=18,000+5400+3,000=26,400cm

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21 ×40×150=18,000+5400+3,000=26,400cm 2

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21 ×40×150=18,000+5400+3,000=26,400cm 2 .

Area of field ABCDEF=Area of rectangle ABDE+Area of ΔBCD+Area of ΔAEF=(120×150)cm 2 +( 21 ×90×120)cm 2 + 21 ×40×150=18,000+5400+3,000=26,400cm 2 .solution