Find the area of the given figure
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Answers
Answer:
Total area of figure=188cm²
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Explanation:
We can see that the given figure is made up of a right angled triangle, a square and a trapezium. We can find the area of whole figure by finding area of each and adding them.
So let's start!!
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Given:
• Height of triangle=10cm
• Base of triangle=8cm
• Side of square=8cm
• Opposite || sides of trapezium=8cm and 20cm.
• Height of whole figure=24cm
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To find:
• Areas of figure
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Solution:
The height of trapezium is not given in the figure so let's find it first!
⇒ Height of whole figure=Height of (∆+Square+Trapezium)
⇒ 24cm=(10cm)+(8cm)+(height of trapezium)
⇒ 24cm-10cm-8cm= Height of trapezium
⇒ 6cm= Height of trapezium
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~Now finding area of trapezium
Area of trapezium=½×(Sum of || sides)× height
Area of trapezium=½×(20cm+8cm)×6cm
Area of trapezium=½×(28cm)×6cm
Area of trapezium=14cm×6cm
Area of trapezium=84cm²
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~Now finding area of square
Area of square=Side²
Area of square=(8cm)²
Area of square=(8cm)×(8cm)
Area of square=64cm²
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~Now finding area of triangle
Area of right angled ∆=½×Base×Height
Area of right angled ∆=½×(8cm)×(10cm)
Area of right angled ∆=4cm×(10cm)
Area of right angled ∆=40cm²
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~Now finding total area
Total area of figure=Area of (∆+Square+Trapezium)
Total area of figure=(40cm²)+(64cm²)+(84cm²)
Total area of figure=40cm²+64cm²+84cm²
Total area of figure=(104cm²)+(84cm²)
Total area of figure=188cm²
So the required total area of figure=188cm²
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Answer:
area of triangle= 1/2 × b ×h
= 1/2 × 8 × 10
= 40 cm square
area of square = 8× 8 = 64 cm square
area of trapezium= 1/2×(p1+p2) ×h
= 1/2 ×(20+8) ×6
= 84 cm square
area of figure = 40+64+84 =188 cm square