Question

Find the area of the given figure where ABCD
is a square with side 20 cm and AXD and BYC
are semicircles. (Use a = 3.14]​

Answer 1

Answer:

314 cm²

Step-by-step explanation:

Given: ABCD is a square with side 20 cm.
To find: Area of given figure.

Area of square = 20 × 20 = 400 cm²

Now, Radius = $\frac{1}{2}$ × Side of square = $\frac{1}{2}$ × 20 = 10 cm
This is because, the diameter = side of square

Area of semicircle = $\frac{\pi r^2}{2} = \frac{3.14 * 10^2}{2} = 3.14 * 50$ = 157 cm²

Area of both semicircles (figure) = 157 × 2 = 314

Therefore, the area of the given figure is 314 cm².