Question

Find the area of the given hexagon which is divided into two trapeziums
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Answer 1

Answer:

area of trapzium = (a+b)h

and area of 2 such trapzium=2(a+b)h

where a=6

b=12

andh=5.2

therefore answer is 187.2

Answer 2

HeYa❤️...

Answer:

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Area Of Hexagon,

$= area \: of \: CDEF \: + \: area \: of \: ABCF \\ = \frac{1}{2} \times h \times (x + y) + \frac{1}{2} \times h \times (x + y) \\ = \frac{1}{2} \times AP \times (ED+ CF) + \frac{1}{2} \times AP \times (CF + AB) \\ = \frac{1}{2} \times 5.2 \times (6 + 12) + \frac{1}{2} \times 5.2 \times (12 + 6)cm \\ = \frac{1}{2} \times 5.2 \times 18 + \frac{1}{2} \times 5.2 \times 18cm \\ = 14.2 + 14.2cm {}^{2} \\ = 23.2cm {}^{2}$

Hence, the area of hexagon is 23.2 cm^2.

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