Question

Find the area of the given pentagon PQRST in which each one of QU, RW and
TV is perpendicular to PS such hat PU = 8 cm, PV = 12 cm, PW = 18 cm,
PS = 24 cm, QU = 6 cm, RW = 8 cm and TV = 10 cm.​

Answer 1

Answer:

288 sq.cm

Step-by-step explanation:

a²+b²=c²

a²+8²=10²

a²+64=100

a²=36

a=6cm

since there are two triangles that measures 6cm and 8cm. so their area would be :

6*8=48 cm²

there are also two triangles :

their area would be 12*16=192cm²

there are also two triangles:

their area should be 12*4=48cm²

their total area should be 48+192+48=288

:.The area of the pentagon is 288cm²

Answer 2

Answer:

THE ANSWER FOR THIS QUESTION IS 288 cm²

MARK ME AS BRAINLIEST AND FOLLOW ME