find the area of the given shape which is rectangular and semicircular at the end.
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Answered by
4
Hi Mate !!!
Required area = ( 68 - 14 ) × 14 + π ( 49)
= 909.86m²
Have a great future ahead
Required area = ( 68 - 14 ) × 14 + π ( 49)
= 909.86m²
Have a great future ahead
Answered by
13
RECTANGLE
length of the rectangle = 68-(7+7)
=54cm
breadth of the rectangle = 14cm
area of the rectangle =14×54
=756cm^2
SEMICIRCLES
diameter =14cm
radius =7cm
area=pi×r×r
=22/7×7×7
=154cm^2
semicircle=154/2
=77
two semicircles=77×2
=154
TOTAL AREA=154+756
=910cm^2
hope it helps!
length of the rectangle = 68-(7+7)
=54cm
breadth of the rectangle = 14cm
area of the rectangle =14×54
=756cm^2
SEMICIRCLES
diameter =14cm
radius =7cm
area=pi×r×r
=22/7×7×7
=154cm^2
semicircle=154/2
=77
two semicircles=77×2
=154
TOTAL AREA=154+756
=910cm^2
hope it helps!
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