Question

find the area of the iron sheet required to build a cuboidal tank of dimension 1.8m * 1.6m*1.4m. also find the capacity of the tank

Answer 1

Answer:

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Answer 2

Answer:

Area of sheet required = 15.28 $m^{2}$

Capacity of tank = 4.032 $m^{3}$

Step-by-step explanation:

Let the length of cuboidal tank, L = 1.8 m

         breadth of cuboidal tank, B = 1.6 m

         height of cuboidal tank, H = 1.4 m

Area of iron sheet required is given by formula = 2[L*B + B*H + H*L]

Total surface area = 2[(1.8 * 1.6) + (1.6 * 1.4) + (1.4 * 1.8)]

                                = 2[2.88 + 2.24 + 2.52]

                                = 2 * 7.64 = 15.28 $m^{2}$

Capacity of cuboidal tank = L * B * H

                                             = 1.8 * 1.6 * 1.4 = 4.032 $m^{3}$