Question

find the area of the irregular polygon

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Answer 1

Step-by-step explanation:

Given : PQRSTUV is a polygon whose side is PV = 16 m , PQ = 5 m ,OR = 5 m , RS= 3m , ST= 6m & VU = 2 m

Find Area Of Polygon

Construction VU is Produce To I

joint QI , PQ = VI

By observation PVQI is a rectangle

Area = 16×5

= 80 cm^2

Joint RU

RU = PV - QR =16 m-5m

= 11 m

By observation RUST is a trapezium

so area = 1/2×6+11×3

= 51/2 cm^2

= 25.5 cm^2

Area of polygon = 80 +25.5

= 105.5 cm^2

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