Question

find the area of the isosceles triangle whose base 30 cm one of its side is 12 cm​

Answer 1

Step-by-step explanation:

Perimeter of isosceles triangle=30cm

Length of equal sides=12cm

Let third side of triangle=xcm

According to problem,

x+12+12=30

x+24=30

x=30−24

x=6

∴ Third side of triangle=6cm

Using Heron's formula

Area of triangle=  root s(s−a)(s−b)(s−c)

Answer 2

Answer:

kya tum meri friend banogi kani