find the area of the isosceles triangle whose each equal side is 10 cm and base is 12 cm
Answers
Answered by
5
a=10cm
b=10cm
c=12cm
s=a+b+c÷2
s=10+10+12÷2
s=16
Area of a triangle =√s(s-a)(s-b)(s-c)
=√16(16-10)(16-10)(16-12)
=√16×6×6×4
=6√4×4×4
=6×4√4
24√4 cm^2
Answered by
2
Answer:
By Pythagoras theorem,
10²=hieght² +6²
100-36=hieght²
√64=height
8cm=height
I hope this much will help you
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