Question

FIND THE AREA OF THE ISSOSCELES TRIANGLE WHISE BASE IS 3 CM AND PERIMETER 8 CM.​

Answer 1

Step-by-step explanation:

Given that the triangle is isosceles

Thus, Two sides of a triangle area equal.

Suppose, a ∆ABC is a isosceles triangle , AB = AC and BC = 3cm

Perimeter of the triangle = 8 cm

Now, let the side of a triangle = x

If AB = x = AC

AB + BC + AC = 8 cm

x + x + 3 = 8 cm

2x = 5 cm

x = 2.5 cm

AB = AC = 2.5 cm

Area of a isosceles triangle =

$2 \times \frac{1}{2} \times \frac{3}{2} \times \sqrt{ {( \frac{5}{2} )}^{2} - ( { \frac{3}{2} )}^{2} } \\ = > \frac{3}{2} \times \sqrt{ \frac{25}{4} - \frac{9}{4} } \\ = > \frac{3}{2} \times \sqrt{ \frac{16}{4} } \\ = > \frac{3}{2} \times \sqrt{4} \\ = > \frac{3}{2} \times 2 \\ = > 3 {cm}^{2}$

Please refer to the figure

Hope you understand it

Thank you