find the area of the length triangle of whose side are 8cm 24cm and
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Step-by-step explanation:
Let 1st side=a
2nd side=b
3rd side =c
Therefore, a+b+c=(8+24+30)cm.
=62cm
Now,½(a+b+c)=½(62)
=31cm.
=s. [Let]
Area of the Triangle=√s(s-a)(s-b)(s-c)
=√31(31-8)(31-24)(31-30)
=√31(23)(7)(1)
=√(31)161
=√4991
=70.65 cm²
Therefore the Required Area is 70.65 cm²
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