find the area of the major segment apb circle of radius 35 cm and ∆aob =90
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Answered by
98
radius of circle = 35 cm
see attachment ,
you can say that , major segment is the sum of right angled triangle and 3/4 th part of circle { as you know, centre of circle is 360° ,means area of complete circle is πr² , means for 360° , area of circle =πr², so, for 270° , area of circular part = 270°/360° πr² = 3/4 πr²}
area of major segment = area of triangle + 3/4 area of circle
= 1/2 height × base + 3/4 πr²
= 1/2 × r × r + 3/4πr²
= r²/4( 2 + 3π)
= r²/4 × (2 + 66/7) = 35 × 35/4 × 80/7
= 35 × 5/4 × 80
= 35 × 5 × 20
= 3500 cm²
Hence, area of major segment is 3500 cm²
see attachment ,
you can say that , major segment is the sum of right angled triangle and 3/4 th part of circle { as you know, centre of circle is 360° ,means area of complete circle is πr² , means for 360° , area of circle =πr², so, for 270° , area of circular part = 270°/360° πr² = 3/4 πr²}
area of major segment = area of triangle + 3/4 area of circle
= 1/2 height × base + 3/4 πr²
= 1/2 × r × r + 3/4πr²
= r²/4( 2 + 3π)
= r²/4 × (2 + 66/7) = 35 × 35/4 × 80/7
= 35 × 5/4 × 80
= 35 × 5 × 20
= 3500 cm²
Hence, area of major segment is 3500 cm²
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Answered by
94
Plz find the attachment for answers
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