Question

Find the area of the maximum circle that can be fit in a square of side 7 cm

Answer 1

The diameter of such a circle is equal to the length of the square’s side. 7 cm in this case.

Area of circle is pi × (d^2)÷4 using 22/7 for pi

22/7 × 7^2 ÷ 4 = 22×7÷4 = 77/2 = 38.5 cm^2

Answer 2

Area of maximum circle is 38.5 sq. cm.

Step-by-step explanation:

Since we have given that

Side of square = 7 cm

Maximum circle that can be fit should have diameter = side of square

So, Diameter = 7 cm

So, Radius = 3.5 cm

So, Area of maximum circle would be

$\pi r^2\\\\=\dfrac{22}{7}\times 3.5\times 3.5\\\\=22\times 0.5\times 3.5\\\\=38.5\ cm^2$

Hence, area of maximum circle is 38.5 sq. cm.

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Find the area of the maximum circle that can be fit in a square of side 7 cm​

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