Math, asked by Mikyman2765, 1 year ago

Find the area of the minor segment formed by a chord which subtends an angle of 60 degreebat the centre of a circle with radius 7 cm

Answers

Answered by Anonymous
4
Area of sector = r^2/2 × pie/3

= 49/2 × 22/7× 3

= 154/6 = 25.66 cm^2

Area of equilateral triangle OAB = √3/4 . ( 7)^2

= 20.825 cm^2

Area of minor segment = area of sector - area of equilateral triangle

= 25.66 -20.825 = 4.835 cm^2



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