Find the area of the minor segment formed by a chord which subtends an angle of 60 degreebat the centre of a circle with radius 7 cm
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Area of sector = r^2/2 × pie/3
= 49/2 × 22/7× 3
= 154/6 = 25.66 cm^2
Area of equilateral triangle OAB = √3/4 . ( 7)^2
= 20.825 cm^2
Area of minor segment = area of sector - area of equilateral triangle
= 25.66 -20.825 = 4.835 cm^2
= 49/2 × 22/7× 3
= 154/6 = 25.66 cm^2
Area of equilateral triangle OAB = √3/4 . ( 7)^2
= 20.825 cm^2
Area of minor segment = area of sector - area of equilateral triangle
= 25.66 -20.825 = 4.835 cm^2
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