Question

find the area of the minor segment of a circle of 28 cm if the length of the corresponding arc APB is 44
$used \: \: \sqrt{} = \frac{22}{7}$
​

Answer 1

Area of the segment = Area of the sector - Area of the triangle

Area of the sector = θ/360°πr²

Area of the triangle = 1/2*AB*sinθ

Here, the length of the arc = 44 cm

Radius = 28 cm

First, we have to find out the angle θ by using the formula of length of the arc.

Then,

44 = θ/360°2πr

θ = (44*7*360)/(2*28*22)

θ = 90°

Now,

Area of the sector = 90/360*22/7*28*28

Area of the sector = 616 sq cm

Area of the triangle = 1/2*28*28*sin90

= 1/2*28*28*1

Area of the triangle =  392 sq cm

Area of the segment = 616 - 392

Area of the sector = 224 sq cm

Answer 2

Answer:

224cm square

Step-by-step explanation:

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