Question

find the area of the minor segment of a circle of a circle of radius 14cm ,when the angle of the corresponding sector is 60digeri

Answer 1

Let the center of circle be O.
Let the radii of the sector be OA and OB.
Given ∠AOB = 60°.  
In the ΔAOB, OA=OB, So it is isosceles.
     =>  ∠OAB = OBA = [180° - ∠AOB ] /2 = 60°
Hence, ΔAOB is equilateral.
   Hence,  AB = OA = 14 cm.

Area of ΔAOB = √3/4 * R²
Area of sector OAB = π R² * (60°/360°) = π R² / 6

Area of minor segment AB :   πR²/ 6 - √3/4 R²
            = 22/7 * 14² /6 - √3 /4 * 14²  cm²
            = 17.75 cm²

Answer 2

Step-by-step explanation:

See the attached picture for the answer to the question