Question

Find the area of the minor segment of a circle of radius 14 cm when its central angle is 60°. Also find the
area of the corresponding major segment.
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Answer 1

Answer:

616/12

Step-by-step explanation:

r=14cm

minor segment =ø/360×πr²

60/360×22/7×14×14

=616/12

Answer 2

Answer:

area of minor segment=area of minor sector-area of triangle

in the triangle

the central angle=60

so by angle sum property the other two angles will also be equal to 60 each

so as all the angles of the triangle are equal to 60 the triangle is an equilateral triangle.

so area of the triangle will be = √3/4 a² where a=radius of the circle

so area of triangle=√3/4 *14*14=49√3cm²  or 84.87cm²

area of minor sector=θ/360*πr²

=60/360*22/7*14*14

=22*49/3

=359.33cm²

area of minor segment=area of minor sector-area of triangle

=359.33cm²-84.87cm²

=274.46cm²

area of major segment=area of circle-area of minor segment

area of circle=πr²

=22/7*14*14

=22*28

=616cm²

area of major segment=area of circle-area of minor segment

=616cm²-274.46cm²

=341.54cm²

therefore the area of the minor segment =274.46cm²

                                     and

area of major segment=341.54cm²

hope it helps