find the area of the minor segment of a circle of radius 42 cm if length of corresponding arc is 44 cm
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we know that r=42 cm and length of corresponding arc= 44 cm
l=πrθ/180
44=22/7*42*θ/180
θ=60°
area of minor segment = πr^2θ/360-1/2r^2 sin θ
= 22/7*42*42*60/360-1/2*42*42*sin60
to solve this you get
= 160.188 cm square.
l=πrθ/180
44=22/7*42*θ/180
θ=60°
area of minor segment = πr^2θ/360-1/2r^2 sin θ
= 22/7*42*42*60/360-1/2*42*42*sin60
to solve this you get
= 160.188 cm square.
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30
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