Question

Find the area of the minor segment of a circle of radius 28cm,where the angle of corresponding sector is 45*

Answer 1

HEY THERE!!

Note; If the circle is divided into two segments, the bigger portion is called the major segment and the smaller portion is called the minor segment.

Question:-

Find the area of the minor segment of a circle of radius 28cm,where the angle of corresponding sector is 45°

Method of Solution!

Given;

Area of the minor segment of a circle of radius 28cm.

the angle of corresponding sector is 45°

Using Formula of Minor Section!

Minor Section => ∅/360° × πr²

=> 45/360° × 3.14 × (28)²

=> 0.125 ×3.41 × 784

=> 334.18 cm²

Hence, Minor Section = 334.18 cm²

Answer 2

HEY MATE HERE IS YOUR ANSWER

$\rule {155}{3}$

Given :-

Radius of circle = 28 cm

Angle corresponding sector = 45 °

____________________________

In this question we use formula of minor section

Minor section =

$\huge = > \frac{o}{360} \times \pi \: {r}^{2}$


$\huge = > \frac{45}{360} \times \frac{22}{7} \times 28 \times 28$



$\huge = > 334.18 \: c {m}^{2}$
Therefore,

Minor section = 334.18 cm^2

$\rule {150} {2}$

Hope it will help you

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